Base | Representation |
---|---|
bin | 1110000101100100111… |
… | …0011111111010011101 |
3 | 212010200110012000111111 |
4 | 3201121032133322131 |
5 | 12431121334012113 |
6 | 303102532222021 |
7 | 23325234522004 |
oct | 3413116377235 |
9 | 763613160444 |
10 | 242015141533 |
11 | 93702268970 |
12 | 3aaa246a911 |
13 | 19a8ba1a979 |
14 | b9dc169c3b |
15 | 6466d1013d |
hex | 385939fe9d |
242015141533 has 4 divisors (see below), whose sum is σ = 264016518048. Its totient is φ = 220013765020.
The previous prime is 242015141531. The next prime is 242015141587. The reversal of 242015141533 is 335141510242.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 242015141533 - 21 = 242015141531 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 242015141495 and 242015141504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (242015141531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11000688241 + ... + 11000688262.
It is an arithmetic number, because the mean of its divisors is an integer number (66004129512).
Almost surely, 2242015141533 is an apocalyptic number.
It is an amenable number.
242015141533 is a deficient number, since it is larger than the sum of its proper divisors (22001376515).
242015141533 is a wasteful number, since it uses less digits than its factorization.
242015141533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22001376514.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 242015141533 its reverse (335141510242), we get a palindrome (577156651775).
The spelling of 242015141533 in words is "two hundred forty-two billion, fifteen million, one hundred forty-one thousand, five hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •