Base | Representation |
---|---|
bin | 110111000011001011110110… |
… | …000010110101010101011011 |
3 | 1011202020121221010220122111101 |
4 | 313003023312002311111123 |
5 | 223213223204202212103 |
6 | 2214532242453012231 |
7 | 101665655021642212 |
oct | 6703136602652533 |
9 | 1152217833818441 |
10 | 242111434413403 |
11 | 70164978992335 |
12 | 231a2999624077 |
13 | a513019825119 |
14 | 43b0382482079 |
15 | 1cecd19c72a1d |
hex | dc32f60b555b |
242111434413403 has 4 divisors (see below), whose sum is σ = 246679574685408. Its totient is φ = 237543294141400.
The previous prime is 242111434413371. The next prime is 242111434413439. The reversal of 242111434413403 is 304314434111242.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 242111434413403 - 25 = 242111434413371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (242111434411403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2284070135923 + ... + 2284070136028.
It is an arithmetic number, because the mean of its divisors is an integer number (61669893671352).
Almost surely, 2242111434413403 is an apocalyptic number.
242111434413403 is a deficient number, since it is larger than the sum of its proper divisors (4568140272005).
242111434413403 is an equidigital number, since it uses as much as digits as its factorization.
242111434413403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4568140272004.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 242111434413403 its reverse (304314434111242), we get a palindrome (546425868524645).
The spelling of 242111434413403 in words is "two hundred forty-two trillion, one hundred eleven billion, four hundred thirty-four million, four hundred thirteen thousand, four hundred three".
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