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2430112010311 = 14615871662653
BaseRepresentation
bin100011010111001101111…
…101101001000001000111
322121022112200110211121001
4203113031331221001013
5304303332133312221
65100213354034131
7340366304161426
oct43271575510107
98538480424531
102430112010311
11857671971217
12332b7b718947
1314820a524b9b
1485891cd72bd
154332d278391
hex235cdf69047

2430112010311 has 4 divisors (see below), whose sum is σ = 2430115134552. Its totient is φ = 2430108886072.

The previous prime is 2430112010273. The next prime is 2430112010351. The reversal of 2430112010311 is 1130102110342.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2430112010311 - 29 = 2430112009799 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2430112010351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 630261 + ... + 2292913.

It is an arithmetic number, because the mean of its divisors is an integer number (607528783638).

Almost surely, 22430112010311 is an apocalyptic number.

2430112010311 is a deficient number, since it is larger than the sum of its proper divisors (3124241).

2430112010311 is a wasteful number, since it uses less digits than its factorization.

2430112010311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3124240.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2430112010311 its reverse (1130102110342), we get a palindrome (3560214120653).

The spelling of 2430112010311 in words is "two trillion, four hundred thirty billion, one hundred twelve million, ten thousand, three hundred eleven".

Divisors: 1 1461587 1662653 2430112010311