243031243401 has 10 divisors (see below), whose sum is σ = 363046672362. Its totient is φ = 162020828880.

The previous prime is 243031243379. The next prime is 243031243453. The reversal of 243031243401 is 104342130342.

243031243401 is a `hidden beast` number, since 2 + 4 + 3 + 0 + 312 + 4 + 340 + 1 = 666.

243031243401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 185567962176 + 57463281225 = 430776^2 + 239715^2 .

It is not a de Polignac number, because 243031243401 - 2⁵ = 243031243369 is a prime.

It is a super-2 number, since 2×243031243401² (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (243031243471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 1500192780 + ... + 1500192941.

Almost surely, 2^243031243401 is an apocalyptic number.

It is an amenable number.

243031243401 is a deficient number, since it is larger than the sum of its proper divisors (120015428961).

243031243401 is an equidigital number, since it uses as much as digits as its factorization.

243031243401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3000385733 (or 3000385724 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 243031243401 its reverse (104342130342), we get a palindrome (347373373743).

The spelling of 243031243401 in words is "two hundred forty-three billion, thirty-one million, two hundred forty-three thousand, four hundred one".