Base | Representation |
---|---|
bin | 100011011000001010111… |
… | …001111010011000100010 |
3 | 22121102011221100210121222 |
4 | 203120022321322120202 |
5 | 304312430404134132 |
6 | 5100503040215042 |
7 | 340433530543034 |
oct | 43301271723042 |
9 | 8542157323558 |
10 | 2431134443042 |
11 | 858047017048 |
12 | 33320600a482 |
13 | 1483412b7876 |
14 | 8594ba03c54 |
15 | 4338cddb412 |
hex | 2360ae7a622 |
2431134443042 has 4 divisors (see below), whose sum is σ = 3646701664566. Its totient is φ = 1215567221520.
The previous prime is 2431134443039. The next prime is 2431134443047. The reversal of 2431134443042 is 2403444311342.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2416970824921 + 14163618121 = 1554661^2 + 119011^2 .
It is a junction number, because it is equal to n+sod(n) for n = 2431134442993 and 2431134443011.
It is not an unprimeable number, because it can be changed into a prime (2431134443047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607783610759 + ... + 607783610762.
Almost surely, 22431134443042 is an apocalyptic number.
2431134443042 is a deficient number, since it is larger than the sum of its proper divisors (1215567221524).
2431134443042 is a wasteful number, since it uses less digits than its factorization.
2431134443042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1215567221523.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 2431134443042 its reverse (2403444311342), we get a palindrome (4834578754384).
The spelling of 2431134443042 in words is "two trillion, four hundred thirty-one billion, one hundred thirty-four million, four hundred forty-three thousand, forty-two".
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