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243114130151 = 882612754491
BaseRepresentation
bin1110001001101010111…
…0110011101011100111
3212020112001010102110122
43202122232303223213
512440344204131101
6303403551312155
723364411003314
oct3423256635347
9766461112418
10243114130151
1194116652322
123b14a51b65b
1319c056061a9
14baa40c3d0b
1564cd54651b
hex389abb3ae7

243114130151 has 4 divisors (see below), whose sum is σ = 243116972904. Its totient is φ = 243111287400.

The previous prime is 243114130121. The next prime is 243114130157. The reversal of 243114130151 is 151031411342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-243114130151 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 243114130151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243114130157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1288985 + ... + 1465506.

It is an arithmetic number, because the mean of its divisors is an integer number (60779243226).

Almost surely, 2243114130151 is an apocalyptic number.

243114130151 is a deficient number, since it is larger than the sum of its proper divisors (2842753).

243114130151 is an equidigital number, since it uses as much as digits as its factorization.

243114130151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2842752.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 243114130151 its reverse (151031411342), we get a palindrome (394145541493).

The spelling of 243114130151 in words is "two hundred forty-three billion, one hundred fourteen million, one hundred thirty thousand, one hundred fifty-one".

Divisors: 1 88261 2754491 243114130151