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243115031423 = 1122101366493
BaseRepresentation
bin1110001001101011001…
…0001111101101111111
3212020112002211012210002
43202122302033231333
512440344422001143
6303404022504515
723364421446035
oct3423262175577
9766462735702
10243115031423
1194117108480
123b14a89513b
1319c058604a4
14baa427a555
1564cd6735b8
hex389ac8fb7f

243115031423 has 4 divisors (see below), whose sum is σ = 265216397928. Its totient is φ = 221013664920.

The previous prime is 243115031371. The next prime is 243115031431. The reversal of 243115031423 is 324130511342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-243115031423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243115031473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11050683236 + ... + 11050683257.

It is an arithmetic number, because the mean of its divisors is an integer number (66304099482).

Almost surely, 2243115031423 is an apocalyptic number.

243115031423 is a deficient number, since it is larger than the sum of its proper divisors (22101366505).

243115031423 is a wasteful number, since it uses less digits than its factorization.

243115031423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22101366504.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 243115031423 its reverse (324130511342), we get a palindrome (567245542765).

The spelling of 243115031423 in words is "two hundred forty-three billion, one hundred fifteen million, thirty-one thousand, four hundred twenty-three".

Divisors: 1 11 22101366493 243115031423