243130000445 has 4 divisors (see below), whose sum is σ = 291756000540. Its totient is φ = 194504000352.

The previous prime is 243130000417. The next prime is 243130000499. The reversal of 243130000445 is 544000031342.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 137857006681 + 105272993764 = 371291^2 + 324458^2 .

It is a cyclic number.

It is not a de Polignac number, because 243130000445 - 2¹² = 243129996349 is a prime.

It is a super-2 number, since 2×243130000445² (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24313000040 + ... + 24313000049.

It is an arithmetic number, because the mean of its divisors is an integer number (72939000135).

Almost surely, 2^243130000445 is an apocalyptic number.

It is an amenable number.

243130000445 is a deficient number, since it is larger than the sum of its proper divisors (48626000095).

243130000445 is an equidigital number, since it uses as much as digits as its factorization.

243130000445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48626000094.

The product of its (nonzero) digits is 5760, while the sum is 26.

Adding to 243130000445 its reverse (544000031342), we get a palindrome (787130031787).

The spelling of 243130000445 in words is "two hundred forty-three billion, one hundred thirty million, four hundred forty-five", and thus it is an aban number.