243141131403 has 10 divisors (see below), whose sum is σ = 363210826044. Its totient is φ = 162094087548.

The previous prime is 243141131399. The next prime is 243141131411. The reversal of 243141131403 is 304131141342.

243141131403 is a `hidden beast` number, since 24 + 314 + 11 + 314 + 0 + 3 = 666.

It is not a de Polignac number, because 243141131403 - 2² = 243141131399 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (243141131803) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 1500871101 + ... + 1500871262.

Almost surely, 2^243141131403 is an apocalyptic number.

243141131403 is a deficient number, since it is larger than the sum of its proper divisors (120069694641).

243141131403 is an equidigital number, since it uses as much as digits as its factorization.

243141131403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3001742375 (or 3001742366 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 243141131403 its reverse (304131141342), we get a palindrome (547272272745).

It can be divided in two parts, 243141 and 131403, that added together give a square (374544 = 612²).

The spelling of 243141131403 in words is "two hundred forty-three billion, one hundred forty-one million, one hundred thirty-one thousand, four hundred three".