243142012033 has 4 divisors (see below), whose sum is σ = 243143018820. Its totient is φ = 243141005248.

The previous prime is 243142011997. The next prime is 243142012037. The reversal of 243142012033 is 330210241342.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 178875705969 + 64266306064 = 422937^2 + 253508^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-243142012033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243142011989 and 243142012007.

It is not an unprimeable number, because it can be changed into a prime (243142012037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99741 + ... + 704437.

It is an arithmetic number, because the mean of its divisors is an integer number (60785754705).

Almost surely, 2^243142012033 is an apocalyptic number.

It is an amenable number.

243142012033 is a deficient number, since it is larger than the sum of its proper divisors (1006787).

243142012033 is an equidigital number, since it uses as much as digits as its factorization.

243142012033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1006786.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 243142012033 its reverse (330210241342), we get a palindrome (573352253375).

The spelling of 243142012033 in words is "two hundred forty-three billion, one hundred forty-two million, twelve thousand, thirty-three".