Base | Representation |
---|---|
bin | 1110001001110001111… |
… | …0100101111110010011 |
3 | 212020121002021012222020 |
4 | 3202130132211332103 |
5 | 12440424204343011 |
6 | 303410515342523 |
7 | 23365215042543 |
oct | 3423436457623 |
9 | 766532235866 |
10 | 243143434131 |
11 | 94131147894 |
12 | 3b1582b1a43 |
13 | 19c0b6c6420 |
14 | baa7d51323 |
15 | 64d0dd4006 |
hex | 389c7a5f93 |
243143434131 has 32 divisors (see below), whose sum is σ = 372156288000. Its totient is φ = 139957279488.
The previous prime is 243143434129. The next prime is 243143434141. The reversal of 243143434131 is 131434341342.
It is not a de Polignac number, because 243143434131 - 21 = 243143434129 is a prime.
It is a super-2 number, since 2×2431434341312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243143434092 and 243143434101.
It is not an unprimeable number, because it can be changed into a prime (243143434141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2018226 + ... + 2135303.
It is an arithmetic number, because the mean of its divisors is an integer number (11629884000).
Almost surely, 2243143434131 is an apocalyptic number.
243143434131 is a deficient number, since it is larger than the sum of its proper divisors (129012853869).
243143434131 is a wasteful number, since it uses less digits than its factorization.
243143434131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4153643.
The product of its digits is 41472, while the sum is 33.
Adding to 243143434131 its reverse (131434341342), we get a palindrome (374577775473).
The spelling of 243143434131 in words is "two hundred forty-three billion, one hundred forty-three million, four hundred thirty-four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •