243144132003131 has 4 divisors (see below), whose sum is σ = 244153028816664. Its totient is φ = 242135235189600.

The previous prime is 243144132003127. The next prime is 243144132003163. The reversal of 243144132003131 is 131300231441342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243144132003131 - 2² = 243144132003127 is a prime.

It is a super-4 number, since 4×243144132003131⁴ (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (243144132003631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504448406405 + ... + 504448406886.

It is an arithmetic number, because the mean of its divisors is an integer number (61038257204166).

Almost surely, 2^{243144132003131} is an apocalyptic number.

243144132003131 is a deficient number, since it is larger than the sum of its proper divisors (1008896813533).

243144132003131 is a wasteful number, since it uses less digits than its factorization.

243144132003131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008896813532.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 243144132003131 its reverse (131300231441342), we get a palindrome (374444363444473).

The spelling of 243144132003131 in words is "two hundred forty-three trillion, one hundred forty-four billion, one hundred thirty-two million, three thousand, one hundred thirty-one".