Base | Representation |
---|---|
bin | 1110001001111111011… |
… | …0011000000110110001 |
3 | 212020202000201002100110 |
4 | 3202133312120012301 |
5 | 12441033200003213 |
6 | 303420300011533 |
7 | 23366502616065 |
oct | 3423766300661 |
9 | 766660632313 |
10 | 243200000433 |
11 | 941600729a5 |
12 | 3b173230ba9 |
13 | 19c1a340500 |
14 | bab1677aa5 |
15 | 64d5d595c3 |
hex | 389fd981b1 |
243200000433 has 24 divisors (see below), whose sum is σ = 356885253120. Its totient is φ = 147208052160.
The previous prime is 243200000401. The next prime is 243200000441. The reversal of 243200000433 is 334000002342.
It is not a de Polignac number, because 243200000433 - 25 = 243200000401 is a prime.
It is a super-2 number, since 2×2432000004332 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (243200000333) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3900913 + ... + 3962766.
It is an arithmetic number, because the mean of its divisors is an integer number (14870218880).
Almost surely, 2243200000433 is an apocalyptic number.
It is an amenable number.
243200000433 is a deficient number, since it is larger than the sum of its proper divisors (113685252687).
243200000433 is a wasteful number, since it uses less digits than its factorization.
243200000433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7863769 (or 7863756 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 21.
Adding to 243200000433 its reverse (334000002342), we get a palindrome (577200002775).
The spelling of 243200000433 in words is "two hundred forty-three billion, two hundred million, four hundred thirty-three", and thus it is an aban number.
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