Base | Representation |
---|---|
bin | 110111010011010111100101… |
… | …100000001001111110111011 |
3 | 1011220011221111122000121000122 |
4 | 313103113211200021332323 |
5 | 223334433314133322042 |
6 | 2221143205150523455 |
7 | 102142215251335202 |
oct | 6723274540117673 |
9 | 1156157448017018 |
10 | 243223553417147 |
11 | 705535910961a6 |
12 | 2334242bb0658b |
13 | a593b62300514 |
14 | 440c1232a4239 |
15 | 1d1bc0964e7d2 |
hex | dd35e5809fbb |
243223553417147 has 4 divisors (see below), whose sum is σ = 244715722456680. Its totient is φ = 241731384377616.
The previous prime is 243223553417137. The next prime is 243223553417153. The reversal of 243223553417147 is 741714355322342.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-243223553417147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (243223553417137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 746084519522 + ... + 746084519847.
It is an arithmetic number, because the mean of its divisors is an integer number (61178930614170).
Almost surely, 2243223553417147 is an apocalyptic number.
243223553417147 is a deficient number, since it is larger than the sum of its proper divisors (1492169039533).
243223553417147 is a wasteful number, since it uses less digits than its factorization.
243223553417147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1492169039532.
The product of its digits is 16934400, while the sum is 53.
The spelling of 243223553417147 in words is "two hundred forty-three trillion, two hundred twenty-three billion, five hundred fifty-three million, four hundred seventeen thousand, one hundred forty-seven".
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