Base | Representation |
---|---|
bin | 110111010011100010100111… |
… | …101000000011011111100101 |
3 | 1011220020002002020211121222220 |
4 | 313103202213220003133211 |
5 | 223340132044422432323 |
6 | 2221152444504342553 |
7 | 102143114652342156 |
oct | 6723424750033745 |
9 | 1156202066747886 |
10 | 243235400202213 |
11 | 7055861030a161 |
12 | 23344797474a59 |
13 | a594ccc7aba03 |
14 | 440c9287db92d |
15 | 1d1c19e7080e3 |
hex | dd38a7a037e5 |
243235400202213 has 8 divisors (see below), whose sum is σ = 324434474558400. Its totient is φ = 162096629657088.
The previous prime is 243235400202167. The next prime is 243235400202257. The reversal of 243235400202213 is 312202004532342.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 243235400202213 - 213 = 243235400194021 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243235400202283) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15075943353 + ... + 15075959486.
It is an arithmetic number, because the mean of its divisors is an integer number (40554309319800).
Almost surely, 2243235400202213 is an apocalyptic number.
It is an amenable number.
243235400202213 is a deficient number, since it is larger than the sum of its proper divisors (81199074356187).
243235400202213 is a wasteful number, since it uses less digits than its factorization.
243235400202213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30151905531.
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 243235400202213 its reverse (312202004532342), we get a palindrome (555437404734555).
The spelling of 243235400202213 in words is "two hundred forty-three trillion, two hundred thirty-five billion, four hundred million, two hundred two thousand, two hundred thirteen".
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