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2432414113 = 10323615671
BaseRepresentation
bin1001000011111011…
…1011000110100001
320021112000102212121
42100332323012201
514440144222423
61041211024241
7114164115223
oct22076730641
96245012777
102432414113
1110390417a8
1257a73b081
132c9c276bc
1419109a413
15e382a45d
hex90fbb1a1

2432414113 has 4 divisors (see below), whose sum is σ = 2456029888. Its totient is φ = 2408798340.

The previous prime is 2432414107. The next prime is 2432414147. The reversal of 2432414113 is 3114142342.

2432414113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2432414113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2432414183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11807733 + ... + 11807938.

It is an arithmetic number, because the mean of its divisors is an integer number (614007472).

Almost surely, 22432414113 is an apocalyptic number.

It is an amenable number.

2432414113 is a deficient number, since it is larger than the sum of its proper divisors (23615775).

2432414113 is a wasteful number, since it uses less digits than its factorization.

2432414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23615774.

The product of its digits is 2304, while the sum is 25.

The square root of 2432414113 is about 49319.5104699955. The cubic root of 2432414113 is about 1344.8664872101.

Adding to 2432414113 its reverse (3114142342), we get a palindrome (5546556455).

The spelling of 2432414113 in words is "two billion, four hundred thirty-two million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 103 23615671 2432414113