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24341032013132 = 226359956952037
BaseRepresentation
bin1011000100011010101101…
…00100010000110101001100
310012011222110101001110201002
411202031112210100311030
511142300413143410012
6123434040555435432
75061403315224002
oct542152644206514
9105158411043632
1024341032013132
117834a7900275a
122891556455b78
131077470a28b83
1460217dd8ca72
152c32758dd7c2
hex162356910d4c

24341032013132 has 12 divisors (see below), whose sum is σ = 42603504731760. Its totient is φ = 12168602089776.

The previous prime is 24341032013113. The next prime is 24341032013141. The reversal of 24341032013132 is 23131023014342.

It is a junction number, because it is equal to n+sod(n) for n = 24341032013095 and 24341032013104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478450583 + ... + 478501454.

It is an arithmetic number, because the mean of its divisors is an integer number (3550292060980).

Almost surely, 224341032013132 is an apocalyptic number.

It is an amenable number.

24341032013132 is a deficient number, since it is larger than the sum of its proper divisors (18262472718628).

24341032013132 is a wasteful number, since it uses less digits than its factorization.

24341032013132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 956958400 (or 956958398 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 24341032013132 its reverse (23131023014342), we get a palindrome (47472055027474).

The spelling of 24341032013132 in words is "twenty-four trillion, three hundred forty-one billion, thirty-two million, thirteen thousand, one hundred thirty-two".

Divisors: 1 2 4 6359 12718 25436 956952037 1913904074 3827808148 6085258003283 12170516006566 24341032013132