243420211312042 has 4 divisors (see below), whose sum is σ = 365130316968066. Its totient is φ = 121710105656020.

The previous prime is 243420211311983. The next prime is 243420211312043. The reversal of 243420211312042 is 240213112024342.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 157431700858041 + 85988510454001 = 12547179^2 + 9272999^2 .

It is a junction number, because it is equal to n+sod(n) for n = 243420211311995 and 243420211312013.

It is not an unprimeable number, because it can be changed into a prime (243420211312043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60855052828009 + ... + 60855052828012.

Almost surely, 2^{243420211312042} is an apocalyptic number.

243420211312042 is a deficient number, since it is larger than the sum of its proper divisors (121710105656024).

243420211312042 is a wasteful number, since it uses less digits than its factorization.

243420211312042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121710105656023.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 243420211312042 its reverse (240213112024342), we get a palindrome (483633323336384).

The spelling of 243420211312042 in words is "two hundred forty-three trillion, four hundred twenty billion, two hundred eleven million, three hundred twelve thousand, forty-two".