243433033111423 has 4 divisors (see below), whose sum is σ = 247423738572328. Its totient is φ = 239442327650520.

The previous prime is 243433033111393. The next prime is 243433033111469. The reversal of 243433033111423 is 324111330334342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-243433033111423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243433033151423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1995352730361 + ... + 1995352730482.

It is an arithmetic number, because the mean of its divisors is an integer number (61855934643082).

Almost surely, 2^{243433033111423} is an apocalyptic number.

243433033111423 is a deficient number, since it is larger than the sum of its proper divisors (3990705460905).

243433033111423 is an equidigital number, since it uses as much as digits as its factorization.

243433033111423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3990705460904.

The product of its (nonzero) digits is 186624, while the sum is 37.

Adding to 243433033111423 its reverse (324111330334342), we get a palindrome (567544363445765).

The spelling of 243433033111423 in words is "two hundred forty-three trillion, four hundred thirty-three billion, thirty-three million, one hundred eleven thousand, four hundred twenty-three".