Base | Representation |
---|---|
bin | 1011000100011110111101… |
… | …00000110000000111100001 |
3 | 10012012012100022202010222120 |
4 | 11202033132200300013201 |
5 | 11142320101033402311 |
6 | 123435055152454453 |
7 | 5061513661441101 |
oct | 542173640600741 |
9 | 105165308663876 |
10 | 24343312794081 |
11 | 7835a39497196 |
12 | 2891a9224a429 |
13 | 10777454021b8 |
14 | 602318c57201 |
15 | 2c335ac65706 |
hex | 1623de8301e1 |
24343312794081 has 64 divisors (see below), whose sum is σ = 34388896577280. Its totient is φ = 15296603811840.
The previous prime is 24343312794061. The next prime is 24343312794107. The reversal of 24343312794081 is 18049721334342.
It is not a de Polignac number, because 24343312794081 - 25 = 24343312794049 is a prime.
It is a super-2 number, since 2×243433127940812 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (24343312794061) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1128195765 + ... + 1128217341.
It is an arithmetic number, because the mean of its divisors is an integer number (537326509020).
Almost surely, 224343312794081 is an apocalyptic number.
It is an amenable number.
24343312794081 is a deficient number, since it is larger than the sum of its proper divisors (10045583783199).
24343312794081 is a wasteful number, since it uses less digits than its factorization.
24343312794081 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23394.
The product of its (nonzero) digits is 3483648, while the sum is 51.
The spelling of 24343312794081 in words is "twenty-four trillion, three hundred forty-three billion, three hundred twelve million, seven hundred ninety-four thousand, eighty-one".
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