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2435425401311 = 7484977174009
BaseRepresentation
bin100011011100001010101…
…010100111100111011111
322121211020222120001210022
4203130022222213213133
5304400222400320221
65102452522302355
7340645053230330
oct43341252474737
98554228501708
102435425401311
11859949169551
123340030579bb
1314887628c726
1485c37856287
154353e9864ab
hex2370aaa79df

2435425401311 has 8 divisors (see below), whose sum is σ = 2783401095840. Its totient is φ = 2087464151808.

The previous prime is 2435425401307. The next prime is 2435425401341. The reversal of 2435425401311 is 1131045245342.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2435425401311 - 22 = 2435425401307 is a prime.

It is a super-3 number, since 3×24354254013113 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2435425401341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3247526 + ... + 3926483.

It is an arithmetic number, because the mean of its divisors is an integer number (347925136980).

Almost surely, 22435425401311 is an apocalyptic number.

2435425401311 is a deficient number, since it is larger than the sum of its proper divisors (347975694529).

2435425401311 is an equidigital number, since it uses as much as digits as its factorization.

2435425401311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7222513.

The product of its (nonzero) digits is 57600, while the sum is 35.

The spelling of 2435425401311 in words is "two trillion, four hundred thirty-five billion, four hundred twenty-five million, four hundred one thousand, three hundred eleven".

Divisors: 1 7 48497 339479 7174009 50218063 347917914473 2435425401311