Base | Representation |
---|---|
bin | 100011100000101111000… |
… | …001101101000101110001 |
3 | 22122021220211011211012121 |
4 | 203200233001231011301 |
5 | 304440244040300423 |
6 | 5105023341354241 |
7 | 341210443102354 |
oct | 43405701550561 |
9 | 8567824154177 |
10 | 2440330400113 |
11 | 860a35989771 |
12 | 334b51868981 |
13 | 149178537b98 |
14 | 8618106829b |
15 | 4372a3c445d |
hex | 2382f06d171 |
2440330400113 has 8 divisors (see below), whose sum is σ = 2441886819008. Its totient is φ = 2438774475984.
The previous prime is 2440330400093. The next prime is 2440330400119. The reversal of 2440330400113 is 3110040330442.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2440330400113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2440330400119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10006756 + ... + 10247722.
It is an arithmetic number, because the mean of its divisors is an integer number (305235852376).
Almost surely, 22440330400113 is an apocalyptic number.
It is an amenable number.
2440330400113 is a deficient number, since it is larger than the sum of its proper divisors (1556418895).
2440330400113 is a wasteful number, since it uses less digits than its factorization.
2440330400113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 247383.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 2440330400113 its reverse (3110040330442), we get a palindrome (5550370730555).
The spelling of 2440330400113 in words is "two trillion, four hundred forty billion, three hundred thirty million, four hundred thousand, one hundred thirteen".
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