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2440440113 = 7930891647
BaseRepresentation
bin1001000101110110…
…0010100100110001
320022002010012110212
42101131202210301
514444223040423
61042055033505
7114322253516
oct22135424461
96262105425
102440440113
111042623861
1258136b895
132cb7a7907
1419218930d
15e43b3578
hex91762931

2440440113 has 4 divisors (see below), whose sum is σ = 2471331840. Its totient is φ = 2409548388.

The previous prime is 2440440109. The next prime is 2440440193. The reversal of 2440440113 is 3110440442.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2440440113 - 22 = 2440440109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2440440193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15445745 + ... + 15445902.

It is an arithmetic number, because the mean of its divisors is an integer number (617832960).

Almost surely, 22440440113 is an apocalyptic number.

It is an amenable number.

2440440113 is a deficient number, since it is larger than the sum of its proper divisors (30891727).

2440440113 is an equidigital number, since it uses as much as digits as its factorization.

2440440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30891726.

The product of its (nonzero) digits is 1536, while the sum is 23.

The square root of 2440440113 is about 49400.8108536692. The cubic root of 2440440113 is about 1346.3440382879.

Adding to 2440440113 its reverse (3110440442), we get a palindrome (5550880555).

The spelling of 2440440113 in words is "two billion, four hundred forty million, four hundred forty thousand, one hundred thirteen".

Divisors: 1 79 30891647 2440440113