2440555133121 has 48 divisors (see below), whose sum is σ = 4036137341184. Its totient is φ = 1392082578432.

The previous prime is 2440555133113. The next prime is 2440555133141. The reversal of 2440555133121 is 1213315550442.

2440555133121 is a `hidden beast` number, since 2 + 4 + 40 + 55 + 513 + 31 + 21 = 666.

2440555133121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 2440555133121 - 2³ = 2440555133113 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2440555133111) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 267102265 + ... + 267111401.

It is an arithmetic number, because the mean of its divisors is an integer number (84086194608).

Almost surely, 2^{2440555133121} is an apocalyptic number.

2440555133121 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

It is an amenable number.

2440555133121 is a deficient number, since it is larger than the sum of its proper divisors (1595582208063).

2440555133121 is a wasteful number, since it uses less digits than its factorization.

2440555133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16350 (or 16347 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

The spelling of 2440555133121 in words is "two trillion, four hundred forty billion, five hundred fifty-five million, one hundred thirty-three thousand, one hundred twenty-one".