Base | Representation |
---|---|
bin | 100011100001110010000… |
… | …001011101100101000111 |
3 | 22122101211011012102222110 |
4 | 203201302001131211013 |
5 | 310000044312110210 |
6 | 5105331053032103 |
7 | 341250342035313 |
oct | 43416201354507 |
9 | 8571734172873 |
10 | 2441454410055 |
11 | 861462403001 |
12 | 335206185633 |
13 | 1492c737421b |
14 | 8624a456b43 |
15 | 43793dee420 |
hex | 2387205d947 |
2441454410055 has 16 divisors (see below), whose sum is σ = 3906359424000. Its totient is φ = 1302098229408.
The previous prime is 2441454410033. The next prime is 2441454410069. The reversal of 2441454410055 is 5500144541442.
It is not a de Polignac number, because 2441454410055 - 25 = 2441454410023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2441454409995 and 2441454410022.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1402654 + ... + 2617316.
It is an arithmetic number, because the mean of its divisors is an integer number (244147464000).
Almost surely, 22441454410055 is an apocalyptic number.
2441454410055 is a deficient number, since it is larger than the sum of its proper divisors (1464905013945).
2441454410055 is a wasteful number, since it uses less digits than its factorization.
2441454410055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1348670.
The product of its (nonzero) digits is 256000, while the sum is 39.
Adding to 2441454410055 its reverse (5500144541442), we get a palindrome (7941598951497).
The spelling of 2441454410055 in words is "two trillion, four hundred forty-one billion, four hundred fifty-four million, four hundred ten thousand, fifty-five".
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