Base | Representation |
---|---|
bin | 1110010001000111000… |
… | …1011100101101110111 |
3 | 212102200020011201211222 |
4 | 3210101301130231313 |
5 | 13003441443424343 |
6 | 304334054020555 |
7 | 23465041524542 |
oct | 3442161345567 |
9 | 772606151758 |
10 | 245111311223 |
11 | 94a50a43a99 |
12 | 3b60734775b |
13 | 1a16330443c |
14 | bc13447859 |
15 | 6598a4da68 |
hex | 3911c5cb77 |
245111311223 has 4 divisors (see below), whose sum is σ = 245171494848. Its totient is φ = 245051127600.
The previous prime is 245111311201. The next prime is 245111311229. The reversal of 245111311223 is 322113111542.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 245111311223 - 212 = 245111307127 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 245111311192 and 245111311201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245111311229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30085703 + ... + 30093848.
It is an arithmetic number, because the mean of its divisors is an integer number (61292873712).
Almost surely, 2245111311223 is an apocalyptic number.
245111311223 is a deficient number, since it is larger than the sum of its proper divisors (60183625).
245111311223 is an equidigital number, since it uses as much as digits as its factorization.
245111311223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60183624.
The product of its digits is 1440, while the sum is 26.
Adding to 245111311223 its reverse (322113111542), we get a palindrome (567224422765).
The spelling of 245111311223 in words is "two hundred forty-five billion, one hundred eleven million, three hundred eleven thousand, two hundred twenty-three".
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