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245121105253 = 673658523959
BaseRepresentation
bin1110010001001001011…
…0110011110101100101
3212102200220121022201211
43210102112303311211
513004002000332003
6304335043551421
723465221005553
oct3442226636545
9772626538654
10245121105253
1194a56523432
123b60a68b571
131a16535331b
14bc14876bd3
15659983596d
hex39125b3d65

245121105253 has 4 divisors (see below), whose sum is σ = 248779629280. Its totient is φ = 241462581228.

The previous prime is 245121105233. The next prime is 245121105259. The reversal of 245121105253 is 352501121542.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 245121105253 - 25 = 245121105221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (245121105259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1829261913 + ... + 1829262046.

It is an arithmetic number, because the mean of its divisors is an integer number (62194907320).

Almost surely, 2245121105253 is an apocalyptic number.

It is an amenable number.

245121105253 is a deficient number, since it is larger than the sum of its proper divisors (3658524027).

245121105253 is an equidigital number, since it uses as much as digits as its factorization.

245121105253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3658524026.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 245121105253 its reverse (352501121542), we get a palindrome (597622226795).

The spelling of 245121105253 in words is "two hundred forty-five billion, one hundred twenty-one million, one hundred five thousand, two hundred fifty-three".

Divisors: 1 67 3658523959 245121105253