Base | Representation |
---|---|
bin | 1110010001001011100… |
… | …0110111001110110011 |
3 | 212102201112101211222222 |
4 | 3210102320313032303 |
5 | 13004011242011201 |
6 | 304340003151255 |
7 | 23465356615322 |
oct | 3442270671663 |
9 | 772645354888 |
10 | 245130032051 |
11 | 94a60570253 |
12 | 3b61167552b |
13 | 1a16715a558 |
14 | bc15b1c0b9 |
15 | 659a4ea91b |
hex | 3912e373b3 |
245130032051 has 4 divisors (see below), whose sum is σ = 245180299392. Its totient is φ = 245079764712.
The previous prime is 245130032041. The next prime is 245130032057. The reversal of 245130032051 is 150230031542.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 245130032051 - 26 = 245130031987 is a prime.
It is a super-2 number, since 2×2451300320512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 245130032051.
It is not an unprimeable number, because it can be changed into a prime (245130032057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25126355 + ... + 25136108.
It is an arithmetic number, because the mean of its divisors is an integer number (61295074848).
Almost surely, 2245130032051 is an apocalyptic number.
245130032051 is a deficient number, since it is larger than the sum of its proper divisors (50267341).
245130032051 is an equidigital number, since it uses as much as digits as its factorization.
245130032051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50267340.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 245130032051 its reverse (150230031542), we get a palindrome (395360063593).
The spelling of 245130032051 in words is "two hundred forty-five billion, one hundred thirty million, thirty-two thousand, fifty-one".
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