245203433110133 has 4 divisors (see below), whose sum is σ = 253113221275008. Its totient is φ = 237293644945260.

The previous prime is 245203433110099. The next prime is 245203433110151. The reversal of 245203433110133 is 331011334302542.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 245203433110133 - 2²⁰ = 245203432061557 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 245203433110093 and 245203433110102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (245203436110133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3954894082391 + ... + 3954894082452.

It is an arithmetic number, because the mean of its divisors is an integer number (63278305318752).

Almost surely, 2^{245203433110133} is an apocalyptic number.

It is an amenable number.

245203433110133 is a deficient number, since it is larger than the sum of its proper divisors (7909788164875).

245203433110133 is an equidigital number, since it uses as much as digits as its factorization.

245203433110133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7909788164874.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 245203433110133 its reverse (331011334302542), we get a palindrome (576214767412675).

The spelling of 245203433110133 in words is "two hundred forty-five trillion, two hundred three billion, four hundred thirty-three million, one hundred ten thousand, one hundred thirty-three".