245400253110013 has 4 divisors (see below), whose sum is σ = 245402834653728. Its totient is φ = 245397671566300.

The previous prime is 245400253109987. The next prime is 245400253110031. The reversal of 245400253110013 is 310011352004542.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 245400253110013 - 2⁵ = 245400253109981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (245400253110083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1290629263 + ... + 1290819388.

It is an arithmetic number, because the mean of its divisors is an integer number (61350708663432).

Almost surely, 2^{245400253110013} is an apocalyptic number.

It is an amenable number.

245400253110013 is a deficient number, since it is larger than the sum of its proper divisors (2581543715).

245400253110013 is an equidigital number, since it uses as much as digits as its factorization.

245400253110013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2581543714.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 245400253110013 in words is "two hundred forty-five trillion, four hundred billion, two hundred fifty-three million, one hundred ten thousand, thirteen".