Base | Representation |
---|---|
bin | 110111110101010000100111… |
… | …111100110100000010000111 |
3 | 1012012102121000202002212010212 |
4 | 313311100213330310002013 |
5 | 224141113100332000403 |
6 | 2230125140234510035 |
7 | 102502404602034554 |
oct | 6765204774640207 |
9 | 1165377022085125 |
10 | 245552540500103 |
11 | 7127127a630791 |
12 | 23659888b9531b |
13 | a702674c47b85 |
14 | 448cb4098da2b |
15 | 1d5c5b9a314d8 |
hex | df5427f34087 |
245552540500103 has 4 divisors (see below), whose sum is σ = 245552573214168. Its totient is φ = 245552507786040.
The previous prime is 245552540500093. The next prime is 245552540500123. The reversal of 245552540500103 is 301005045255542.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 245552540500103 - 234 = 245535360630919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245552540500123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1142900 + ... + 22190342.
It is an arithmetic number, because the mean of its divisors is an integer number (61388143303542).
Almost surely, 2245552540500103 is an apocalyptic number.
245552540500103 is a deficient number, since it is larger than the sum of its proper divisors (32714065).
245552540500103 is a wasteful number, since it uses less digits than its factorization.
245552540500103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32714064.
The product of its (nonzero) digits is 600000, while the sum is 41.
Adding to 245552540500103 its reverse (301005045255542), we get a palindrome (546557585755645).
The spelling of 245552540500103 in words is "two hundred forty-five trillion, five hundred fifty-two billion, five hundred forty million, five hundred thousand, one hundred three".
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