Base | Representation |
---|---|
bin | 111000110110001011001110… |
… | …001001111100101010100010 |
3 | 1012210020001120000212010202001 |
4 | 320312023032021330222202 |
5 | 230232210124240430214 |
6 | 2243422341342114214 |
7 | 103442610502543600 |
oct | 7066131611745242 |
9 | 1183201500763661 |
10 | 250013505014434 |
11 | 7273114a818697 |
12 | 2405a360b7b96a |
13 | a9672318a3155 |
14 | 45a4a0aa96870 |
15 | 1dd8659659c74 |
hex | e362ce27caa2 |
250013505014434 has 12 divisors (see below), whose sum is σ = 436248054668214. Its totient is φ = 107148645006144.
The previous prime is 250013505014423. The next prime is 250013505014443. The reversal of 250013505014434 is 434410505310052.
250013505014434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 243430673130225 + 6582831884209 = 15602265^2 + 2565703^2 .
It is a junction number, because it is equal to n+sod(n) for n = 250013505014393 and 250013505014402.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1275579107119 + ... + 1275579107314.
Almost surely, 2250013505014434 is an apocalyptic number.
250013505014434 is a deficient number, since it is larger than the sum of its proper divisors (186234549653780).
250013505014434 is a wasteful number, since it uses less digits than its factorization.
250013505014434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2551158214449 (or 2551158214442 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 250013505014434 in words is "two hundred fifty trillion, thirteen billion, five hundred five million, fourteen thousand, four hundred thirty-four".
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