25001365047 has 4 divisors (see below), whose sum is σ = 33335153400. Its totient is φ = 16667576696.

The previous prime is 25001365021. The next prime is 25001365049. The reversal of 25001365047 is 74056310052.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25001365047 - 2⁷ = 25001364919 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25001364999 and 25001365017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25001365049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4166894172 + ... + 4166894177.

It is an arithmetic number, because the mean of its divisors is an integer number (8333788350).

Almost surely, 2^25001365047 is an apocalyptic number.

25001365047 is a deficient number, since it is larger than the sum of its proper divisors (8333788353).

25001365047 is an equidigital number, since it uses as much as digits as its factorization.

25001365047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8333788352.

The product of its (nonzero) digits is 25200, while the sum is 33.

Adding to 25001365047 its reverse (74056310052), we get a palindrome (99057675099).

The spelling of 25001365047 in words is "twenty-five billion, one million, three hundred sixty-five thousand, forty-seven".