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2500315315 = 5500063063
BaseRepresentation
bin1001010100000111…
…1100100010110011
320110020210011210221
42111001330202303
520110040042230
61052034233511
7115650221011
oct22501744263
96406704727
102500315315
1110733a99a3
12599425897
1330b00cb24
1419a0d38b1
15e978e27a
hex9507c8b3

2500315315 has 4 divisors (see below), whose sum is σ = 3000378384. Its totient is φ = 2000252248.

The previous prime is 2500315309. The next prime is 2500315327. The reversal of 2500315315 is 5135130052.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2500315315 - 25 = 2500315283 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2500315315.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250031527 + ... + 250031536.

It is an arithmetic number, because the mean of its divisors is an integer number (750094596).

Almost surely, 22500315315 is an apocalyptic number.

2500315315 is a deficient number, since it is larger than the sum of its proper divisors (500063069).

2500315315 is an equidigital number, since it uses as much as digits as its factorization.

2500315315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 500063068.

The product of its (nonzero) digits is 2250, while the sum is 25.

The square root of 2500315315 is about 50003.1530505827. The cubic root of 2500315315 is about 1357.2658656714.

Adding to 2500315315 its reverse (5135130052), we get a palindrome (7635445367).

The spelling of 2500315315 in words is "two billion, five hundred million, three hundred fifteen thousand, three hundred fifteen".

Divisors: 1 5 500063063 2500315315