2501000113 has 4 divisors (see below), whose sum is σ = 2581677568. Its totient is φ = 2420322660.

The previous prime is 2501000087. The next prime is 2501000119. The reversal of 2501000113 is 3110001052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2501000113 - 2¹³ = 2500991921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2501000093 and 2501000102.

It is not an unprimeable number, because it can be changed into a prime (2501000119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40338681 + ... + 40338742.

It is an arithmetic number, because the mean of its divisors is an integer number (645419392).

Almost surely, 2^2501000113 is an apocalyptic number.

It is an amenable number.

2501000113 is a deficient number, since it is larger than the sum of its proper divisors (80677455).

2501000113 is an equidigital number, since it uses as much as digits as its factorization.

2501000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80677454.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 2501000113 is about 50010.0001299740. Note that the first 3 decimals coincide. The cubic root of 2501000113 is about 1357.3897657923.

Subtracting from 2501000113 its sum of digits (13), we obtain a square (2501000100 = 50010²).

Adding to 2501000113 its reverse (3110001052), we get a palindrome (5611001165).

The spelling of 2501000113 in words is "two billion, five hundred one million, one hundred thirteen", and thus it is an aban number.