Base | Representation |
---|---|
bin | 111000111010100011000101… |
… | …110110101000010101110010 |
3 | 1012211021210012222111000222011 |
4 | 320322203011312220111302 |
5 | 230302121044420142232 |
6 | 2244212400440433134 |
7 | 103503406413210454 |
oct | 7072430566502562 |
9 | 1184253188430864 |
10 | 250314013443442 |
11 | 72837638a09153 |
12 | 240a86487787aa |
13 | a989682b48610 |
14 | 45b53975462d4 |
15 | 1de1396799547 |
hex | e3a8c5da8572 |
250314013443442 has 8 divisors (see below), whose sum is σ = 404353406331756. Its totient is φ = 115529544666192.
The previous prime is 250314013443407. The next prime is 250314013443803. The reversal of 250314013443442 is 244344310413052.
250314013443442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 197460081098401 + 52853932345041 = 14052049^2 + 7270071^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 250314013443395 and 250314013443404.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4813731027733 + ... + 4813731027784.
Almost surely, 2250314013443442 is an apocalyptic number.
250314013443442 is a deficient number, since it is larger than the sum of its proper divisors (154039392888314).
250314013443442 is a wasteful number, since it uses less digits than its factorization.
250314013443442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9627462055532.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 250314013443442 its reverse (244344310413052), we get a palindrome (494658323856494).
The spelling of 250314013443442 in words is "two hundred fifty trillion, three hundred fourteen billion, thirteen million, four hundred forty-three thousand, four hundred forty-two".
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