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25043530413345 = 354094082075047
BaseRepresentation
bin1011011000110111001101…
…01110111111010100100001
310021200010201200201202020020
411230123212232333110201
511240303122241211340
6125132501122304053
75163223013134113
oct554334656772441
9107603650652206
1025043530413345
117a859a1042414
12298572b7b8029
1310c8796985022
146281830093b3
152d668dea79d0
hex16c6e6bbf521

25043530413345 has 16 divisors (see below), whose sum is σ = 40167618472320. Its totient is φ = 13323892950144.

The previous prime is 25043530413287. The next prime is 25043530413431. The reversal of 25043530413345 is 54331403534052.

It is not a de Polignac number, because 25043530413345 - 29 = 25043530412833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25043530413297 and 25043530413306.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2041031389 + ... + 2041043658.

It is an arithmetic number, because the mean of its divisors is an integer number (2510476154520).

Almost surely, 225043530413345 is an apocalyptic number.

It is an amenable number.

25043530413345 is a deficient number, since it is larger than the sum of its proper divisors (15124088058975).

25043530413345 is a wasteful number, since it uses less digits than its factorization.

25043530413345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4082075464.

The product of its (nonzero) digits is 1296000, while the sum is 42.

Adding to 25043530413345 its reverse (54331403534052), we get a palindrome (79374933947397).

The spelling of 25043530413345 in words is "twenty-five trillion, forty-three billion, five hundred thirty million, four hundred thirteen thousand, three hundred forty-five".

Divisors: 1 3 5 15 409 1227 2045 6135 4082075047 12246225141 20410375235 61231125705 1669568694223 5008706082669 8347843471115 25043530413345