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2505143151131 = 5970981598189
BaseRepresentation
bin100100011101000110001…
…010101110101000011011
322212111012201210201012112
4210131012022232220123
5312021013121314011
65154502531502535
7345663532305215
oct44350612565033
98774181721175
102505143151131
11886474aaa905
1234561b457a4b
131523070b242a
148936cb995b5
15452703e258b
hex247462aea1b

2505143151131 has 8 divisors (see below), whose sum is σ = 2547643354800. Its totient is φ = 2462644285920.

The previous prime is 2505143151113. The next prime is 2505143151169. The reversal of 2505143151131 is 1311513415052.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2505143151131 is a prime.

It is a super-2 number, since 2×25051431511312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2505143159131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3888785 + ... + 4486973.

It is an arithmetic number, because the mean of its divisors is an integer number (318455419350).

Almost surely, 22505143151131 is an apocalyptic number.

2505143151131 is a deficient number, since it is larger than the sum of its proper divisors (42500203669).

2505143151131 is an equidigital number, since it uses as much as digits as its factorization.

2505143151131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 669229.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 2505143151131 its reverse (1311513415052), we get a palindrome (3816656566183).

The spelling of 2505143151131 in words is "two trillion, five hundred five billion, one hundred forty-three million, one hundred fifty-one thousand, one hundred thirty-one".

Divisors: 1 59 70981 598189 4187879 35293151 42460053409 2505143151131