Base | Representation |
---|---|
bin | 100100011101001001110… |
… | …100110000011101110101 |
3 | 22212111101000020120111111 |
4 | 210131021310300131311 |
5 | 312021124323002331 |
6 | 5154513002435021 |
7 | 345665205621664 |
oct | 44351164603565 |
9 | 8774330216444 |
10 | 2505204500341 |
11 | 8864a66a2434 |
12 | 345637b02a71 |
13 | 152316a1253a |
14 | 89376da8ddb |
15 | 452759aedb1 |
hex | 24749d30775 |
2505204500341 has 16 divisors (see below), whose sum is σ = 2643770606400. Its totient is φ = 2367313603200.
The previous prime is 2505204500339. The next prime is 2505204500363. The reversal of 2505204500341 is 1430054025052.
2505204500341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2505204500341 - 21 = 2505204500339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2505204500311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23868465 + ... + 23973193.
It is an arithmetic number, because the mean of its divisors is an integer number (165235662900).
Almost surely, 22505204500341 is an apocalyptic number.
It is an amenable number.
2505204500341 is a deficient number, since it is larger than the sum of its proper divisors (138566106059).
2505204500341 is a wasteful number, since it uses less digits than its factorization.
2505204500341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107940.
The product of its (nonzero) digits is 24000, while the sum is 31.
Adding to 2505204500341 its reverse (1430054025052), we get a palindrome (3935258525393).
The spelling of 2505204500341 in words is "two trillion, five hundred five billion, two hundred four million, five hundred thousand, three hundred forty-one".
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