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25052131254011 = 31180553476701
BaseRepresentation
bin1011011001000111001110…
…11000100101111011111011
310021200221221002201201120112
411230203213120211323323
511240423231100112021
6125140442404214535
75163646111104251
oct554434730457373
9107627832651515
1025052131254011
117a89604a922a4
12298733009a44b
1310c9537829564
1462875b3d85d1
152d69e40d9d5b
hex16c8e7625efb

25052131254011 has 4 divisors (see below), whose sum is σ = 25132684731024. Its totient is φ = 24971577777000.

The previous prime is 25052131253957. The next prime is 25052131254013. The reversal of 25052131254011 is 11045213125052.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25052131254011 - 234 = 25034951384827 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25052131254013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40276738040 + ... + 40276738661.

It is an arithmetic number, because the mean of its divisors is an integer number (6283171182756).

Almost surely, 225052131254011 is an apocalyptic number.

25052131254011 is a deficient number, since it is larger than the sum of its proper divisors (80553477013).

25052131254011 is an equidigital number, since it uses as much as digits as its factorization.

25052131254011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80553477012.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 25052131254011 its reverse (11045213125052), we get a palindrome (36097344379063).

The spelling of 25052131254011 in words is "twenty-five trillion, fifty-two billion, one hundred thirty-one million, two hundred fifty-four thousand, eleven".

Divisors: 1 311 80553476701 25052131254011