251104000213 has 4 divisors (see below), whose sum is σ = 273931636608. Its totient is φ = 228276363820.

The previous prime is 251104000181. The next prime is 251104000223. The reversal of 251104000213 is 312000401152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 251104000213 - 2⁵ = 251104000181 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (251104000223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11413818181 + ... + 11413818202.

It is an arithmetic number, because the mean of its divisors is an integer number (68482909152).

Almost surely, 2^251104000213 is an apocalyptic number.

It is an amenable number.

251104000213 is a deficient number, since it is larger than the sum of its proper divisors (22827636395).

251104000213 is a wasteful number, since it uses less digits than its factorization.

251104000213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22827636394.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 251104000213 its reverse (312000401152), we get a palindrome (563104401365).

The spelling of 251104000213 in words is "two hundred fifty-one billion, one hundred four million, two hundred thirteen", and thus it is an aban number.