Base | Representation |
---|---|
bin | 1110100111100010100… |
… | …0100011111101001001 |
3 | 220000012211011112002202 |
4 | 3221320220203331021 |
5 | 13103304243031441 |
6 | 311211330205545 |
7 | 24100166540330 |
oct | 3517050437511 |
9 | 800184145082 |
10 | 251132002121 |
11 | 975605171a0 |
12 | 408077238b5 |
13 | 1a8b2765c30 |
14 | c224cc0d17 |
15 | 67ec3c219b |
hex | 3a78a23f49 |
251132002121 has 64 divisors (see below), whose sum is σ = 361032215040. Its totient is φ = 168097628160.
The previous prime is 251132002109. The next prime is 251132002151. The reversal of 251132002121 is 121200231152.
It is not a de Polignac number, because 251132002121 - 218 = 251131739977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 251132002093 and 251132002102.
It is not an unprimeable number, because it can be changed into a prime (251132002151) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1431605 + ... + 1597421.
It is an arithmetic number, because the mean of its divisors is an integer number (5641128360).
Almost surely, 2251132002121 is an apocalyptic number.
It is an amenable number.
251132002121 is a deficient number, since it is larger than the sum of its proper divisors (109900212919).
251132002121 is a wasteful number, since it uses less digits than its factorization.
251132002121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165954.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 251132002121 its reverse (121200231152), we get a palindrome (372332233273).
The spelling of 251132002121 in words is "two hundred fifty-one billion, one hundred thirty-two million, two thousand, one hundred twenty-one".
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