Base | Representation |
---|---|
bin | 1110100111100010110… |
… | …0100001110110000111 |
3 | 220000012220010100121211 |
4 | 3221320230201312013 |
5 | 13103310024321210 |
6 | 311211404352251 |
7 | 24100211431240 |
oct | 3517054416607 |
9 | 800186110554 |
10 | 251133042055 |
11 | 97561067545 |
12 | 40807b45687 |
13 | 1a8b2a3b38c |
14 | c2250b1cc7 |
15 | 67ec52a38a |
hex | 3a78b21d87 |
251133042055 has 16 divisors (see below), whose sum is σ = 353719437120. Its totient is φ = 167551310592.
The previous prime is 251133042049. The next prime is 251133042143. The reversal of 251133042055 is 550240331152.
It is a cyclic number.
It is not a de Polignac number, because 251133042055 - 29 = 251133041543 is a prime.
It is a super-3 number, since 3×2511330420553 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96961270 + ... + 96963859.
It is an arithmetic number, because the mean of its divisors is an integer number (22107464820).
Almost surely, 2251133042055 is an apocalyptic number.
251133042055 is a deficient number, since it is larger than the sum of its proper divisors (102586395065).
251133042055 is a wasteful number, since it uses less digits than its factorization.
251133042055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193925178.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 251133042055 in words is "two hundred fifty-one billion, one hundred thirty-three million, forty-two thousand, fifty-five".
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