25113440141 has 4 divisors (see below), whose sum is σ = 25122873312. Its totient is φ = 25104006972.

The previous prime is 25113440087. The next prime is 25113440147. The reversal of 25113440141 is 14104431152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-25113440141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25113440141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25113440147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4712591 + ... + 4717916.

It is an arithmetic number, because the mean of its divisors is an integer number (6280718328).

Almost surely, 2^25113440141 is an apocalyptic number.

It is an amenable number.

25113440141 is a deficient number, since it is larger than the sum of its proper divisors (9433171).

25113440141 is an equidigital number, since it uses as much as digits as its factorization.

25113440141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9433170.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 25113440141 its reverse (14104431152), we get a palindrome (39217871293).

The spelling of 25113440141 in words is "twenty-five billion, one hundred thirteen million, four hundred forty thousand, one hundred forty-one".