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25114122533132 = 226278530633283
BaseRepresentation
bin1011011010111010101100…
…10110100011100100001100
310021220212221101020222202022
411231131112112203210030
511242432210332030012
6125225134004345312
75201302240222403
oct555352626434414
9107825841228668
1025114122533132
11800292649a886
1229973509a5238
1311023369994c9
1462b75c51663a
152d842157b472
hex16d7565a390c

25114122533132 has 6 divisors (see below), whose sum is σ = 43949714432988. Its totient is φ = 12557061266564.

The previous prime is 25114122533117. The next prime is 25114122533141. The reversal of 25114122533132 is 23133522141152.

It is a junction number, because it is equal to n+sod(n) for n = 25114122533092 and 25114122533101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3139265316638 + ... + 3139265316645.

It is an arithmetic number, because the mean of its divisors is an integer number (7324952405498).

Almost surely, 225114122533132 is an apocalyptic number.

It is an amenable number.

25114122533132 is a deficient number, since it is larger than the sum of its proper divisors (18835591899856).

25114122533132 is a wasteful number, since it uses less digits than its factorization.

25114122533132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6278530633287 (or 6278530633285 counting only the distinct ones).

The product of its digits is 43200, while the sum is 35.

Adding to 25114122533132 its reverse (23133522141152), we get a palindrome (48247644674284).

The spelling of 25114122533132 in words is "twenty-five trillion, one hundred fourteen billion, one hundred twenty-two million, five hundred thirty-three thousand, one hundred thirty-two".

Divisors: 1 2 4 6278530633283 12557061266566 25114122533132