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25124342341 = 73589191763
BaseRepresentation
bin10111011001100001…
…110000101001000101
32101211221212211102211
4113121201300221011
5402423312423331
615313021503421
71546414246330
oct273141605105
971757784384
1025124342341
11a72304429a
124a52111b71
1324a5220a77
141304ab3617
159c0a848b1
hex5d9870a45

25124342341 has 4 divisors (see below), whose sum is σ = 28713534112. Its totient is φ = 21535150572.

The previous prime is 25124342339. The next prime is 25124342393. The reversal of 25124342341 is 14324342152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25124342341 - 21 = 25124342339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25124342641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1794595875 + ... + 1794595888.

It is an arithmetic number, because the mean of its divisors is an integer number (7178383528).

Almost surely, 225124342341 is an apocalyptic number.

It is an amenable number.

25124342341 is a deficient number, since it is larger than the sum of its proper divisors (3589191771).

25124342341 is an equidigital number, since it uses as much as digits as its factorization.

25124342341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3589191770.

The product of its digits is 23040, while the sum is 31.

Adding to 25124342341 its reverse (14324342152), we get a palindrome (39448684493).

The spelling of 25124342341 in words is "twenty-five billion, one hundred twenty-four million, three hundred forty-two thousand, three hundred forty-one".

Divisors: 1 7 3589191763 25124342341