Base | Representation |
---|---|
bin | 100100100100011010110… |
… | …001011101110111001001 |
3 | 22220020111122100012120020 |
4 | 210210122301131313021 |
5 | 312133113242340040 |
6 | 5202243015251053 |
7 | 346362415265202 |
oct | 44443261356711 |
9 | 8806448305506 |
10 | 2513005043145 |
11 | 889839918723 |
12 | 347054379a89 |
13 | 152c8ab2b43c |
14 | 898b6d925a9 |
15 | 4558070bcd0 |
hex | 2491ac5ddc9 |
2513005043145 has 32 divisors (see below), whose sum is σ = 4060241482752. Its totient is φ = 1327127428032.
The previous prime is 2513005043123. The next prime is 2513005043161. The reversal of 2513005043145 is 5413405003152.
2513005043145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2513005043145 - 29 = 2513005042633 is a prime.
It is a super-2 number, since 2×25130050431452 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16925722 + ... + 17073548.
It is an arithmetic number, because the mean of its divisors is an integer number (126882546336).
Almost surely, 22513005043145 is an apocalyptic number.
It is an amenable number.
2513005043145 is a deficient number, since it is larger than the sum of its proper divisors (1547236439607).
2513005043145 is a wasteful number, since it uses less digits than its factorization.
2513005043145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 158941.
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 2513005043145 in words is "two trillion, five hundred thirteen billion, five million, forty-three thousand, one hundred forty-five".
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