Base | Representation |
---|---|
bin | 100100100100011110100… |
… | …101000101101110100011 |
3 | 22220020200002111211220000 |
4 | 210210132211011232203 |
5 | 312133231120014202 |
6 | 5202253220151043 |
7 | 346364122155351 |
oct | 44443645055643 |
9 | 8806602454800 |
10 | 2513068907427 |
11 | 889871978921 |
12 | 347071838483 |
13 | 152c9b12c260 |
14 | 898c16587d1 |
15 | 4558612491c |
hex | 2491e945ba3 |
2513068907427 has 40 divisors (see below), whose sum is σ = 4043511961104. Its totient is φ = 1546257148992.
The previous prime is 2513068907407. The next prime is 2513068907449. The reversal of 2513068907427 is 7247098603152.
It is a happy number.
2513068907427 is a `hidden beast` number, since 2 + 5 + 130 + 6 + 89 + 0 + 7 + 427 = 666.
It is not a de Polignac number, because 2513068907427 - 27 = 2513068907299 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2513068907407) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 6523528 + ... + 6898010.
It is a 1-persistent number, because it is pandigital, but 2⋅2513068907427 = 5026137814854 is not.
Almost surely, 22513068907427 is an apocalyptic number.
2513068907427 is a gapful number since it is divisible by the number (27) formed by its first and last digit.
2513068907427 is a deficient number, since it is larger than the sum of its proper divisors (1530443053677).
2513068907427 is a wasteful number, since it uses less digits than its factorization.
2513068907427 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 380881 (or 380872 counting only the distinct ones).
The product of its (nonzero) digits is 5080320, while the sum is 54.
The spelling of 2513068907427 in words is "two trillion, five hundred thirteen billion, sixty-eight million, nine hundred seven thousand, four hundred twenty-seven".
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