Search a number
-
+
25131404345 = 55026280869
BaseRepresentation
bin10111011001111100…
…101100110000111001
32101212110011121200112
4113121330230300321
5402432114414340
615313433114105
71546531261265
oct273174546071
971773147615
1025131404345
11a727028063
124a54558935
1324a6824278
1413059d10a5
159c14cc065
hex5d9f2cc39

25131404345 has 4 divisors (see below), whose sum is σ = 30157685220. Its totient is φ = 20105123472.

The previous prime is 25131404327. The next prime is 25131404359. The reversal of 25131404345 is 54340413152.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5195093929 + 19936310416 = 72077^2 + 141196^2 .

It is a cyclic number.

It is not a de Polignac number, because 25131404345 - 224 = 25114627129 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2513140430 + ... + 2513140439.

It is an arithmetic number, because the mean of its divisors is an integer number (7539421305).

Almost surely, 225131404345 is an apocalyptic number.

It is an amenable number.

25131404345 is a deficient number, since it is larger than the sum of its proper divisors (5026280875).

25131404345 is an equidigital number, since it uses as much as digits as its factorization.

25131404345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5026280874.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 25131404345 its reverse (54340413152), we get a palindrome (79471817497).

The spelling of 25131404345 in words is "twenty-five billion, one hundred thirty-one million, four hundred four thousand, three hundred forty-five".

Divisors: 1 5 5026280869 25131404345