2513311531 has 4 divisors (see below), whose sum is σ = 2515779000. Its totient is φ = 2510844064.

The previous prime is 2513311529. The next prime is 2513311547. The reversal of 2513311531 is 1351133152.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2513311531 - 2¹ = 2513311529 is a prime.

It is a super-2 number, since 2×2513311531² = 12633469703715127922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2513311496 and 2513311505.

It is not an unprimeable number, because it can be changed into a prime (2513311561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1232206 + ... + 1234243.

It is an arithmetic number, because the mean of its divisors is an integer number (628944750).

Almost surely, 2^2513311531 is an apocalyptic number.

2513311531 is a deficient number, since it is larger than the sum of its proper divisors (2467469).

2513311531 is a wasteful number, since it uses less digits than its factorization.

2513311531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2467468.

The product of its digits is 1350, while the sum is 25.

The square root of 2513311531 is about 50132.9385833306. The cubic root of 2513311531 is about 1359.6134157498.

Adding to 2513311531 its reverse (1351133152), we get a palindrome (3864444683).

The spelling of 2513311531 in words is "two billion, five hundred thirteen million, three hundred eleven thousand, five hundred thirty-one".